F(x)=x^2+2.4x-2.4

Solution for F(x)=x^2+2.4x-2.4 equation:

(F)=F^2+2.4F-2.4

We move all terms to the left:

(F)-(F^2+2.4F-2.4)=0

We get rid of parentheses

-F^2+F-2.4F+2.4=0

We add all the numbers together, and all the variables

-1F^2-1.4F+2.4=0

a = -1; b = -1.4; c = +2.4;
Δ = b2-4ac
Δ = -1.42-4·(-1)·2.4
Δ = 11.56
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.4)-\sqrt{11.56}}{2*-1}=\frac{1.4-\sqrt{11.56}}{-2}
$
$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.4)+\sqrt{11.56}}{2*-1}=\frac{1.4+\sqrt{11.56}}{-2}
$